161.\Tthe Product Of Two Numbers Is 120 And The Sum Of Their Squares Is 289. The Sum Of The Two Numbers Is (A)\T23\T(B)\T7 (C)\T13\T(D)\T169

161. The product of two numbers is 120 and the sum of their squares is 289. The sum of the two numbers is (a) 23 (b) 7 (c) 13 (d) 169

  The answer is A

explanation
(x+y)=x^2+y^2+2xy

=>(x+y)^2=289+2(120)

=>(x+y)=√529

=23

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